Std 6 th Mathematics- 15. Triangles and their Properties
Question 1:
Answer 1:
Therefore, △PQR is a right angle traingle.
In △XYZ, ∠Y = 125∘ (an obtuse angle)
Therefore, △XYZ is an obtuse angle traingle.
In △LMN, all angles are acute angles.
Therefore, △LMN is a acute angle traingle.
Question 2:
Answer 2:
Therefore, △ABC is an equilateral traingle.
In △DEF, all sides are different.
Therefore, △DEF is a scalene traingle.
In △UVQ, two sides are equal.
Therefore, △UVW is an isosceles traingle.
Question 3:
As shown in the figure, Avinash is standing near his house. He can choose from two roads to go to school. Which way is
shorter? Explain why.
Answer 3:
Therefore, in △ABC, AC < AB + BC.
Hence, the shortest way to reach school is via AC.
Question 4:
(1) 3 cm, 4 cm, 5 cm (2) 3.4 cm, 3.4 cm, 5 cm
(3) 4.3 cm, 4.3 cm, 4.3 cm (4) 3.7 cm, 3.4 cm, 4 cm
Answer 4:
All sides are different.
Therefore, it is a scalene traingle.
(2)
Two sides are equal.
Therefore, it is an isosceles traingle.
(3)
All sides are equal.
Therefore, it is an equilateral traingle.
(4)
All sides are different.
Therefore, it is a scalene traingle.
Question 5:
(1) 17 cm, 7 cm, 8 cm (2) 7 cm, 24 cm, 25 cm
(3) 9 cm, 6 cm, 16 cm (4) 8.4 cm, 16.4 cm, 4.9 cm
(5) 15 cm, 20 cm, 25 cm (6) 12 cm, 12 cm, 16 cm
Answer 5:
Here, 17 > 7 + 8 or 17 > 15
In any triangle, the sum of the lengths of any two sides of a triangle is always greater than the third side.
Therefore, the traingle is not possible.
(2) 7 cm, 24 cm, 25 cm
Here, 7 < 24 + 25 or 7 < 49
24 < 7 + 25 or 24 < 32
25 < 7 + 24 or 25 < 31
In any triangle, the sum of the lengths of any two sides of a triangle is always greater than the third side.
Therefore, the traingle is possible.
(3) 9 cm, 6 cm, 16 cm
Here, 16 > 9 + 6 or 16 > 15
In any triangle, the sum of the lengths of any two sides of a triangle is always greater than the third side.
Therefore, the traingle is not possible.
(4) 8.4 cm, 16.4 cm, 4.9 cm
Here, 16.4 > 8.4 + 4.9 or 16.4 > 13.3
In any triangle, the sum of the lengths of any two sides of a triangle is always greater than the third side.
Therefore, the traingle is not possible.
(5) 15 cm, 20 cm, 25 cm
Here, 15 < 20 + 25 or 15 < 45
20 < 15 + 25 or 20 < 40
25 < 15 + 20 or 25 < 35
In any triangle, the sum of the lengths of any two sides of a triangle is always greater than the third side.
Therefore, the traingle is possible.
(6) 12 cm, 12 cm, 16 cm
Here, 12 < 12 + 16 or 12 < 28
12 < 12 + 16 or 12 < 28
16 < 12 + 12 or 16 < 24
In any triangle, the sum of the lengths of any two sides of a triangle is always greater than the third side.
Therefore, the traingle is possible.